1. In the equation PV-nRT, R is the gas constant, and has a value of 0.0821 L at
ID: 588499 • Letter: 1
Question
1. In the equation PV-nRT, R is the gas constant, and has a value of 0.0821 L atm/ mol- K. a. If the hot water bath is at a temperature of 95.6°C when you seal the flask, what temperature should you use in the equation? ( Show work) b. If the volume of the container holding the gas is 255 cm', what volume should you use in the equation?( show work) 2. How will you know when the pressure in the flask is equal to the pressure in the room? (Be specific) 3. The volume of the container will be determined by using the density and mass of water in the flask at the temperature of the water used to fill the flask. The density of water at 20.0°C is 0.99821 g/cm3 and at 30.0°C it is 0.99565 g/cm? a. Interpolate between the two given values and determine the density of water at 23.6°C.(Show work) hr what volume will 225.35 grams of water occupy at 23.6"C? ( Show work)Explanation / Answer
Answer:
1) Given ideal gas equation, PV=nRT, where R= gas constant=0.0821 L atm/mol. K.
a) Given temperature of the water bath T=95.6°C
The gas constant value has unit in kelvin. So we have to convert T from °C to K
The temperature used in this reaction is T=95.6 °C=95.6+273 K=368.6 K.
b) Given volume of the container V=255 cm3.
But in R value the volume is in litre. So we have to convert cm3 to Litre.
Since 1 cm3=10-3 L
So volume used in this equation is V=0.255 L.
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