2. (a ) Given the following data, calculate the heat absorbed by the solution an

Question

2. (a ) Given the following data, calculate the heat absorbed by the solution and the heat absorbed by the calorimeter in the following reaction: HNO3 + KOH KNO3 (aq) + H2O, From these, calculate the heat released by the reaction; assuming the density and the specic heat are the same as distilled water: Temperature of 50.0 mL of HNO3 before mixing: Temperature of 50.0 mL of KOH before mixing: Temperature of 100.0 mL of reaction mixture: 22.0 °C 22.0 °C 34.5 C 0ml) (lpa!)(12,5)(4.(34.zgt') 2013. 12.5°C Absorbed by solution: J. Absorbed by calorimeter:J. Heat of reaction:J (b) If the solutions are each 2.0 M, the final concentration of the KNOs is 1.0 M. (Do you know why? n, M1Vi M2V2.) Calculate the molar enthalpy of neutralization, AHN ase.) (NB: Since the concentrations are the same, it is a stoichiometric ratio; no limiting reagent in this c kJ/mol

Explanation / Answer

2 a)

heat absorbed by solution = m*s*DT

                            = 100*4.184*(34.5-22)

                            = 5.23 kj

heat absorbed by calorimeter = o kj

heat of reaction = 5.23 kj

b) if each 2.0 M

no of mol of KOH reacted = 50*2/1000 = 0.1 mol

enthalpy of neutralisation(DHn) = -q/n

                                 = -5.23/0.1

                                 = -52.3 kj/mol

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