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The equilibrium PC15 (g) PC13(g) + Cl2 (g) -92.5 kJ can be shifted toward more p

ID: 589500 • Letter: T

Question

The equilibrium PC15 (g) PC13(g) + Cl2 (g) -92.5 kJ can be shifted toward more product formation by (SLO 4 Question 3) -3. a) Increasing temperature b) increasing pressure c) decreasing temperature d) increasing the concentration of PCl3 4. Consider the following reaction: 2NOBr (g) 2NO (g) + Br2(g). After equilibrium was reached some NOBr was removed to the system, while the temperature was kept at 300 K. This will result in: (SLO 4 Question 4) a) An increase in Kp b) A decrease in Kp c) A shift in the equilibrium position to the right d) A shift in the equilibrium position to the left e) None of these 5. The equilibrium pressure of NO2 in the reaction N204 (g) 2NO2 (g) is 0.56 atm. Its pressure on the addition of a catalyst will be (SLO 4 Question 5) 1.06 atm a) b) 0.75 atm c) 1.56 atm d) 0.56 atm e) none of these

Explanation / Answer

3).

The answer is A because the formation of product is the Endothermic reaction. Endothermic reactions are favoured at high temperatures according to lechatelier principle.

In the formation of product side number of moles are increases. so low pressure is required.

Increasing the concentration of PCl3 , backword reaction is favoured.

4)NOBr is removed from the reaction, the equilibrium shifted towords to the left side. i,e backword reaction favoured.

The answer is D.

5)The answer is D because there is no effect of catalyst on equilibrium condition. only it helps the attainment of equilibrium is fast.

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