Map Sapling Learning macmillan learning The first step in the reaction of Alka-S

Question

Map Sapling Learning macmillan learning The first step in the reaction of Alka-Seltzer with stomach acid consists of one mole of sodium bicarbonate (NaHCO3) reacting with one mole of hydrochloric acid (HCI) to produce one mole of carbonic acid (H2CO3), and one mole of sodium chloride (NaCI) Using this chemical stoichiometry, determine the number of moles of carbonic acid that can be produced from 4 mol of NaHCO3 and 8 mol of HCI. Number mol H, CO Which of the two reactants limits the number of moles of H2CO3 that can be made? How much excess reactant remains after the reaction? Number O NaHCOs O HC mol

Explanation / Answer

1)
Balanced chemical equation is:
NaHCO3 + HCl ---> H2CO3 + NaCl


1 mol of NaHCO3 reacts with 1 mol of HCl
for 4 mol of NaHCO3, 4 mol of HCl is required
But we have 8 mol of HCl

so, NaHCO3 is limiting reagent
we will use NaHCO3 in further calculation

According to balanced equation
mol of H2CO3 formed = (1/1)* moles of NaHCO3
= (1/1)*4
= 4 mol
Answer: 4 mol H2CO3

2)
NaHCO3

3)

According to balanced equation
mol of HCl reacted = (1/1)* moles of NaHCO3
= (1/1)*4
= 4 mol
mol of HCl remaining = mol initially present - mol reacted
mol of HCl remaining = 8 - 4
mol of HCl remaining = 4 mol

Answer: 4 mol

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