a) Suppose 0.20 M NaCl is placed in arm A and 0.30 M NaCI is same levels intiall
ID: 590197 • Letter: A
Question
a) Suppose 0.20 M NaCl is placed in arm A and 0.30 M NaCI is same levels intially. What would happen to the liquid levels afler eoqul n ar b) Supposed you the had used 0.20 M NaCland 0.10 M CaC, again both to the same levels initially What would happen to the levels at equilibrium? had used 0.15 M sucrose and 0.20 M glucose again both to the same levels c) Supposed you initially. What happen to the levels at equilibrium? 2. When 50.0 mL of 1.00 M HCI was mixed with 50.0 mL. of 1.00 M NaOIl in a ca temperature rose from 25.0 °C to 31.5°C. Calculate the heat change for the reaction, assumi the total volume of the solution is 100.0 mL of density 1.0 g/mL, and specific heat 1.00 cal/ (g. °C) a). write a balanced equation for the reaction b). how many moles of HCI (aq) and NaOH have reacted? c). is the reaction exothermic or endothermic? d). how many calories are evolved in the reaction? e), what is H for the above reaction in kJ/mol.Explanation / Answer
2. Neutralization reaction
a) balanced equation,
HCl + NaOH --> NaCl + H2O
b) moles of HCl = moles of NaOH = 1 M x 0.05 ml = 0.05 mol
c) Final temperature was greater than the initial temperature of the solution, therefore, this is an exothermic reaction. Heat is evolved.
d) heat q = mCpdT
= (100 ml x 1 g/ml) x 1 cal/g.oC x (31.5 - 25) = 650 cal
e) dH = -q/mol = -650 cal x 4.18 J/0.05 mol x 1000 = -54.34 kJ/mol
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