Assume you are performing the calibration step of Experiment 8 and you begin wit

Question

Assume you are performing the calibration step of Experiment 8 and you begin with 30 g of water at 20 degrees C and 30 g of water at 80 degrees C. After adding the two portions of water into your calorimeter setup and following the procedure outlined in the experiment, you determine he temperature of the mixed portions of water to be 45 degrees Celsius. What is the heat capacity of he calorimeter? Assume you are performing the calibration step of Experiment 8 and you begin with 30 g of water at 20 degrees C and 30 g of water at 80 degrees C. After adding the two portions of water into your calorimeter setup and following the procedure outlined in the experiment, you determine he temperature of the mixed portions of water to be 45 degrees Celsius. What is the heat capacity of he calorimeter?

Explanation / Answer

heat q = mCpdT

m = mass of water

Cp = specific heat of water

dT = change in temperature

so,

heat lost by hot water,

q(hot water) = 30 x 4.18 (80 - 45) = 4389 J

heat gained by cold water

q(cold water) = 30 x 4.18 (45 - 20) = 3135 J

heat gained by calorimeter,

q(calorimeter) = 4389 - 3135 = 1254 J

heat capacity of calorimeter = 1254 J/(45 - 20) oC = 50.16 J/oC

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