1. If water is added to 0.80 g of NaOH to bring the volume of the solution to 15
ID: 590563 • Letter: 1
Question
1. If water is added to 0.80 g of NaOH to bring the volume of the solution to 150.0 mL, what is the theoretical molarity of the sodium hydroxide solution? If we titrate 10.00 mL of a 0.200 M HCI solution with the sodium hydroxide, we find it requires 19.87 mL to reach the end point. Write the equation and calculate the experimental molárity of the NaOH base. 2. If a sulfuric acid solution is titrated with the above sodium hydroxide solution, it requires 45.20 mL of the NaOH to reach the end point. Write the equation and calculate the mass (in grams) of sulfuric acid in the acid solution sample. 3.Explanation / Answer
1) The mass of NaOH = 0.80 g
Molar mass of NaOH = 39.99 g/mol
Moles of NaOH = 0.02
Volume of the solution = 150.0 ml
Molarity = No. of moles / Volume of solution (L)
= 0.02 / 0.15
= 0.13 M
2) The equation is :-
HCl + NaOH --------> NaCl + H2O
Molarity of HCl(M1) = 0.2 M
Volume of HCl (V1) = 10.0 ml
Volume of NaOH(V2) = 19.87 ml
At the end point the no. of moles of acid and base are equal
M1 x V1 = M2 x V2
0.2 x 10.0 = M2 x 19.87
M2 = 0.1006
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