REPORT FOR EXPERIMENT 19 (continued) NAME 5. On the graph paper provided, plot t
ID: 590698 • Letter: R
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Explanation / Answer
Question 2
Moles of dry air in constant pressure
PV=nRT
V = 125 ml = 0.125 Liter n = Moles = ?
R = 0.0821 L atm K-1 atm-1 T = 273 + 230 = 503K
n = V / RT
n = 0.125 / 0.0821 x 503 = 0.0030269 Moles
using the mole value we can calculate the volume in new temperature
V = 0.0030269 x 0.0821 x 373
Volume = 0.09269 Liter or 92.6 ml
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