B. Miscibility 1. Draw the structural drawing of each requested solvent. Assume

Question

B. Miscibility 1. Draw the structural drawing of each requested solvent. Assume carbons (in reality it is a mixture of many hydrocarbons.) If a solvent has both a polar section and a non-polar section, circle the polar section and put a rectangle around the non-polar section of the drawing. a. water H, H H b. ethanol (CH3CH,OH) H – I-0- I -- H H H | 1 H I-U- I – J – -H c. 1-butanol (CH3CH2CH2CH2OH) H-C | | | d. 1-hexanol (CH;CH,CH;CH,CH,CH,OH) 1 ! H -C - C - . e. kerosene (hydrocarbon with 10 to 16 carbons) I – J –* 7-0-3 I –) -I I-U- * / USU N, H -c C. non-polare. kerosene U-U I I GC 2. List the solvents in order of increasing polarity and explain your reasoning. water Kerosene , l-hexanol, -butanol, ethanol,

Explanation / Answer

Water is a polar solvent as it contain an oxygen which has higher electronegativity ,hexanol ,butanol ,ethanol all contain a OH group which gives it a polarity nature which makes its miscibility with polar solvent high . Kerosene is a hydrocarbons of nearly 10 to 16 carbons which contain non polar bonds hence it is a non polar compound

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