OWLV2 1 Onli... unit circle Practica Solve the e Chegg Study Need Help Webassi N

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OWLV2 1 Onli... unit circle Practica Solve the e Chegg Study Need Help Webassi Need Help Chapter 11: Mastery 1. Reaction Rate and Stoichiometry1 pts 2. Rate Law: Write and Apply 3. Determinine Rate Law: Initial Rates 1 pts 4. Integrated Rate Lew Calculations: 1..1 ptsM Use the References to access important values if needed or this question. 1 pts M In a study of the decomposition of hydrogen iodide on a gold surface at 150°C the following data were obtained: HI]. M 35x102 782 374 187 4.68x10 912 6. Graphical Method: Order and k fro... 1pts 521 7. Half-life and Order from Concent.. 1 pts 2req Hint: It is not necessary to graph these data. The observed half life for this reaction when the starting concentration is 0.374 M is s and when the starting concentration is 0.187 M is 8. Reaction Coordinate Diagramspts . E or k from Arhenius Plot Info 1 pts The average rate of disappearance of HI from t = 0 s to t = 521 s is 10. Mechanisms: First Step Slow. Cat 1 pts 11. Reaction Coordinate Diagrams Inc. ,1 pts The average rate of disappearance of HI from t = 521 s to t = 782 s is Based on these data, the rate constant for this order reaction is Submit Answer Retry Entire Group 6 more group attempts remaining Progress: 10/11 groups Due Dec 3 at 11:55 PM Previous Next Finish Assignment Email Instructor Save and Exit Cengage Learning | Cengage Technical Support

Explanation / Answer

For the given reaction and the reaction data,

(1) rate constant k = (0.374 - 0.187)/521 = 3.59 x 10^-4 M/s

the half-life when initial concentration is 0.374 M = (0.374)/2 x 3.59 x 10^-4 = 520.89 s

the half-life when initial concentration is 0.187 M = (0.187)/2 x 3.59 x 10^-4 = 260.44 s

(2) average rate of reaction (for t=0s and t=521s) = -(0.187 - 0.340)/521= 3.59 x 10^-4 M/s

(3) average rate of reaction (for t=521s and t=782s) = -(9.35 x 10^-2 - 0.187)/(782 - 521) = 3.58 x 10^-4 M/s

(4) rate constant for the reaction = 3.585 x 10^-4 M/s

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