A welder using a tank of volume 7.00×10 2 m3 fills it with oxygen (with a molar

Question

A welder using a tank of volume 7.00×102 m3 fills it with oxygen (with a molar mass of 32.0 g/mol ) at a gauge pressure of 3.20×105 Pa and temperature of 39.0 C. The tank has a small leak, and in time some of the oxygen leaks out. On a day when the temperature is 23.2 C, the gauge pressure of the oxygen in the tank is 2.00×105 Pa .

Part A

Find the initial mass of oxygen.

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Part B

Find the mass of oxygen that has leaked out.

A welder using a tank of volume 7.00×102 m3 fills it with oxygen (with a molar mass of 32.0 g/mol ) at a gauge pressure of 3.20×105 Pa and temperature of 39.0 C. The tank has a small leak, and in time some of the oxygen leaks out. On a day when the temperature is 23.2 C, the gauge pressure of the oxygen in the tank is 2.00×105 Pa .

Part A

Find the initial mass of oxygen.

m = kg

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Incorrect; Try Again; 2 attempts remaining

Part B

Find the mass of oxygen that has leaked out.

m =   kg

Explanation / Answer

As per Ideal gas equation

PV = nRT

At initial condition

P = 3.20×105 Pa = 3.158 atm

V = 7.00×102 m3 = 70 L

R = 0.082057 L atm mol-1K-1

T = 39oC = 312 K

n= ?

n= 8.64 moles

mass of one mole of O2 is 32 g

mass of 8.64 moles = 276.49 g

Part A answer is 0.27649 kg

Part B

similarly at T 23oC = 296.2 K
P= 1.97 atm

V = 7.00×102 m3 = 70 L

n = 5.677

mass = 181.68 (this is the mass remaining)

then the mass of O2 released = 94.8 g = 0.0948 kg

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