The following is a portion of the Reduction Potential Table from your text (Tabl
ID: 592771 • Letter: T
Question
The following is a portion of the Reduction Potential Table from your text (Table 18.1, Zumdahl), with half-reactions ordered as described in the Introduction to this experiment. half-reaction +3eMnO2 + 2 H,0 02 + 2H2O + 4e-. Cr3+ 3eCr Li +e Li a. Which species is the reducing agent in the first half-reaction? b. Which species in the table is the strongest reducing agent? c. Which species in the table is the strongest oxidizing agent? d. Is the reaction of Cr with MnO, to produce Cr and MnO, spontaneous? e. Write the balanced chemical equation for the reaction of Cr" with Li. (Take into account the discussion on p. 123.)Explanation / Answer
reduction potential of mno4- is +1.51V
reduction potential of o2 is 0.4V
reduction potential of cr3+ is -0.74V
reduction potential of li+ is -3.085V
since we know the lower the reduction potential , the lower will be the ability to gain electrons and reduce ....hence oxidising property decreases...li+ is the reducing agent as it has lowest reduction potential...
b.Li+ is the strongest reducing agent as it cant oxidise other substance due to lowest reduction potential....
c.Mno4- is the strongest oxidsing agent as it has the highest reduction potential...
d.yes the reaction is possible because mno4- has the most positive reduction potential which makes it strongest oxidising agent....
e.Cr3+ + 3e----> Cr
3Li ----->3Li+ + 3e
Cr3+ + 3Li ----->Cr + 3Li+
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.