Determining vitamin c lab For two samples which were apple juice and lime juice.
ID: 593081 • Letter: D
Question
Determining vitamin c lab For two samples which were apple juice and lime juice. Did not extract because foods were liquids. Titrated with DCIP. Titration for apple juice was total amount of DCIP 10.33ml. How do I set up this problem to get vitamin c per ml solution??? Also standard titration of DCIP was 2.5 mg vitamin c / 13.38 ml DCIP= 0.187 mg vit c/ ml DCIP Determining vitamin c lab For two samples which were apple juice and lime juice. Did not extract because foods were liquids. Titrated with DCIP. Titration for apple juice was total amount of DCIP 10.33ml. How do I set up this problem to get vitamin c per ml solution??? Also standard titration of DCIP was 2.5 mg vitamin c / 13.38 ml DCIP= 0.187 mg vit c/ ml DCIP For two samples which were apple juice and lime juice. Did not extract because foods were liquids. Titrated with DCIP. Titration for apple juice was total amount of DCIP 10.33ml. How do I set up this problem to get vitamin c per ml solution??? Also standard titration of DCIP was 2.5 mg vitamin c / 13.38 ml DCIP= 0.187 mg vit c/ ml DCIPExplanation / Answer
For this experiment vitaminC(ascorbic acid) standard solution is required. prepare the standard solution of vitaminC and standardised with DCIP (Determine how much titrant was required for your standard).
If you needed an average of 20.00 ml of DCIP solution to react 0.250 grams of vitamin C, then you can determine how much vitamin C was in a sample. For example, if you needed 12.00 ml to react your juice 25ml (assumption)
20.00 ml DCIP solution / 0.250 g Vit C = 12.00 ml DCIP solution / X ml Vit C
50.00 X = 12.00
X = 0.24 g Vit C in that sample.
Keep in mind the volume of your sample, so you can make other calculations, such as grams per liter. For a 25 ml juice sample, for example:
0.24 g / 25 ml = 0.24 g / 0.025 L = 12.00 g/L of vitamin C in that sample.
per ml solution divide 12/1000 = 0.012g
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.