calculate the percent error of your observed value versus the reference value fo
ID: 593239 • Letter: C
Question
calculate the percent error of your observed value versus the reference value for all three portions of the lab. Give an acceptable source of error for each percent error..
104 Experiment 14 Heat Effects and Calorimetry Mass of beaker plus solid Mass of water, muo Mass of solid, m, Initial temperature Final temperature duso for the reaction (Eq. 1) (S.H. 4.18 J/g C) AFH for the reaction (Eq. 5) The quantity you have just calculated is approximately* equal to the heat of solution of your sample. Calculate 475 joul 47 joules the heat of solution per gram of solid sample. AH,olution =-tas joul 22o The solution reaction is endothermic exothermic. (Underline the correct answer.) Give your reasoning. Solid unknown # Optional Fornula of compound used (Gif furnished) Heat of solution per mole of compound C. Heat of Neutralization Molar mass g/mol or 20-6 23 33 C Initial temperature of HCl solution Initial temperature of NaOH solution Final temperature of neutralized mixture Change in temperature. Ar (use the average of the initial temperatures of 23-3c HCI and NaOH) 4m20 (assume 50.0 mL of solution and use average density of 1.02 g/mL) 2 J Total H for the neutralization reaction AH per mole of H' and OH ions reacting kJ/mol S71 The value of 11 will be approximate for several reasons. One is that we do not include the amount This effect is smaller than the likely experimental error, and thus we will ignore it. of heExplanation / Answer
1.
Observed Hsolution = -195 J/g (exothermic)
Reference value of Hsolution = -220 J/g
% error = (Observed value – Reference value) / Reference value * 100
= (-195 + 220) / 220 * 100 = 11.4 %
Sources of error:
a. Experimental error in measuring weights and temperature.
b. Amount of heat absorbed by solute is not considered.
c. S.H of water is assumed constant. It varies with temperature.
2.
Observed Hsolution = -20.6 J/g (exothermic)
Reference value of Hsolution = -23 J/g
% error = (Observed value – Reference value) / Reference value * 100
= (-20.6 + 23) / 23 * 100 = 10.4 %
Sources of error:
a. Experimental error in measuring weights and temperature.
b. Amount of heat absorbed by solute is not considered.
c. S.H of water is assumed constant. It varies with temperature.
3.
Observed Hneutralization = -52.9 J/g (exothermic)
Reference value of Hneutralization = -58.2 J/g
% error = (Observed value – Reference value) / Reference value * 100
= (-52.9 + 58.2) / 58.2 * 100 = 9.1 %
Sources of error:
a. Experimental error in measuring weights and temperature.
b. Amount of heat absorbed by ions is not considered.
c. S.H of water and density of water are assumed constant. It varies with temperature.
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