Two partially miscible liquids A and B are described the regular solution model.

Question

Two partially miscible liquids A and B are described the regular solution model. A temperature composition diagram is shown below. Answer the questions on the reverse side based on the diagrams shown below Temperature composition diagram 440.000 425.000 410.000 395.000 380.000 2 350.000 335.000 2 320.000 E 305.000 290.000 275.000 260.000 245.000 230.000 215.000 200.000 185.000 170.000 140.000 125.000 0.000 0.100 0.200 0.300 0.400 0.500 0.600 0.700 0.800 0.900 1.000 mole fraction, xA mG/T vs x at 298.15 K for a specified total n 0.000 0.200 -0.300 0.400 0.500 0.600 -o -0700 0.900 1.000

Explanation / Answer

a

Xa = 0.5

T = 400 K

This point lies outside the done So only gaseous phae exist

b.

T = 298 K

Since this point lies inside the dome, 2 phases exist - liquid and vapors

at 298 K

mole fraction of extreme 1 = 350 C

mole fraction of extreme 2 = 125 C

mole fraction of liq= (350-298)/(350-125)

= 0.23

mole fraction of vapor phase = 1-.23

= .77

c.

In the second graph we can see that it shows a local maxima at x=0.5

d.

In a phase separation preocess

entrolpy= -G/T

but here T is constant .

So only G can be varied

On way to vay G is to reduce X i.e decease the mole fraction of one component . In this way G becomes more and more neagtive as shown in second plot and phase separation occurs more spontaneously/

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