3. How many mL of a 1% w/w solution of dextrose are need to obtain 50 mg of this

Question

3. How many mL of a 1% w/w solution of dextrose are need to obtain 50 mg of this sugar? (5 points) . Due to the evidence that chlorofluorocarbon (CFC) damage the ozone layer in the atmosphere, this compound was prohibited in 1996. However, there are still 100 million cars that used CFC- 12 (CF C) on their air conditioning systems. How many kg of chloride its accumulated in the atmosphere each year if each of this cars contains 1.1 kg of CFC-12 and 25% of the compound escapes to the atmosphere? (10 puntos S. Mercury is a toxin that attacks then central nervous system. For this reason the Safe Drinking Water Act establish a limit of 0.0020 ppm. Supose that water is contaminated with mercury in a concentration that is doble the ammount established by law, how many liters of contaminated water is required to ingest 50.0 mg of mercury? (8 puntos)

Explanation / Answer

1) Answer:

Glucose mono meric unit is called Dextrose.

weight % = 1

weight of dextrose = 50 mg = 50 x 10-3 g

volume of solution (V) = ?

Molarity (M) = (weight% x 10) / molar mass

M = (1 x 10) / 180

M = 0.0555M

M = (wt / molar mass) x (1000 / V in mL)

0.0555 = (50 x 10-3 / 180) / (1000 / V in mL)

V =  (50 x 10-3 / 180) / (1000 / 0.0555)

V = 50 / (180 x 0.0555)

V = 50 / 9.99

V = 5 mL

Hence the volume = 5 mL

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