1. 1.000 gram of lead sulfate, PbS04(fw 303.2) is mixed with 1.000g of potassium

Question

1. 1.000 gram of lead sulfate, PbS04(fw 303.2) is mixed with 1.000g of potassium chromate,k2cr04(FW 194.2) in 100ml of water. The reaction produce the percipitate lead chromate quantitatively, pbcr04(FW 323.2).
a. write the balnced chemical equation.
b. which reactant is limiting agent and why?
c.how much lead chromate is generated in grams?
d.what are the concentrations of [CrO4]^-2 and [Pb^+2] (ksp= 1.8*10^-14).

. Use the correct propagation of uncertainty method to calculate the result and uncertainity of the percent chloride from the formula and data below:
%cl = 100* (Vol Agno3) (M Agno3) (A W CL)/(Wt Sample)(1000ml/L)
Data for calculations:
Vol Agno3 = 27.33 +- 0.02 ml
M Agno3 = 0.1010 +- 0.0002M
AW CL = 35.453 +- 0.001 gram
Wt Sample = 0.6524 +- 0.0003 gram
1000ml/l is a pure number.

Explanation / Answer

a)PbSO4 + K2CrO4 -----> PbCrO4 + K2SO4 b) m(PbSO4) = 1/303.2 m(K2CrO4) = 1/194.2 since m(PbSO4) [Pb]2+ + [ CrO4} 2- 10/303.2 M 0 0 10/303.2 - x x x ksp = x^2 /(10/303.2 -x) x=2.436 x 10^-8 M

Related Questions

Navigate

• Browse (All)
• Browse 1
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.