To solve stoichiometry problems, you must always calculate numbers of moles. Rec

Question

To solve stoichiometry problems, you must always calculate numbers of moles. Recall that molarity, M, is equal to the concentration in moles per liter: M = mol/L When solutions of silver nitrate and magnesium chloride are mixed, silver chloride precipitates out of solution according to the equation 2AgNO3(aq) + MgCl2(aq) rightarrow 2AgCl(s) + Mg(NO3)2(aq) What mass of silver chloride can be produced from 1.76L of a 0.276 M solution of silver nitrate? Express your answer with the appropriate units. The reaction described in Part A required 3.30L of magnesium chloride. What is the concentration of this magnesium chloride solution? Express your answer with the appropriate units.

Explanation / Answer

molar mass of AgCl = 143.3 g/mol
moles of AgCl = moles of AgNO3 = 1.76 x 0.276 = 0.486 mol
mass of AgCl = moles x molar mass = 0.486 x 143.3 = 69.6 g

moles of MgCl2 = moles of AgNO3 / 2 = 0.486/2 = 0.243 mol
molarity of MgCl2 = moles/volume = 0.243 / 3.30 = 0.0736 M

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