Write a balanced equation for the overall reaction. Electrons flow from left to

Question

Write a balanced equation for the overall reaction. Electrons flow from left to right (anode to cathode). Anode=Pb(s) in 1M Pb2+
cathode= Cl2(g) in 1M Cl-
have a salt bridge between beakers containing NaNO3 (aq)

thank you

Explanation / Answer

we need to reverse one of them into its oxidation: reduction: ClO2 & 1 electron --> (ClO2) -1 Eo = 0.95 volts Oxidation: Mn ---> Mn2+ + 2 electrons Eo = + 1.18 volts Your answer is Eo cell = 2.13 volts Yes, we have to break into half reactions and look up cell potential value... knowing that different references do not agree on voltages... be sure to compare the half cell voltages to your text... & do not double or triple, Eo does not change by balancing equations ======================================… oxidation @ the Anode : Pb(s) --> Pb2+(aq) & 2 e- Eo = + 0.126 volts reduction @ the Cathode: Cl2(g) & 2 e- --> 2 Cl- Eo = + 1.359 volts Your reaction is: Cl2(g) & Pb(s) --> Pb2+(aq) & 2 Cl- (aq)

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