If you did not heat the crucible and its contents following the reaction to a co

Question

If you did not heat the crucible and its contents following the reaction to a constant mass you may have affected the ratio of oxygen to magnesium. How will this error affect the empirical formula determination if some magnesium metal remains unreacted? Explain using the words "high", "Low", or "unaffected".



Grams of magnesium: ____________________
Grams of Compound: ___________________________
Grams of Oxygen:
Moles of Magnesium:_________________
Moles of Oxygen:______________________
Ratio of moles of oxygen to moles of magnesium:_______________

Explanation / Answer

If your sample is a hydrated copper chloride, the loss in mass of copper chloride due to error will be accounted as part of the water content. So the mass ratio wil be affected.

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