Consider the following equation: 2N2O (g) ?? 2N2 (g) + O2 (g) a. At 25?C, the Kc

Question

Consider the following equation: 2N2O (g) ?? 2N2 (g) + O2 (g)
a. At 25?C, the Kc value for this reaction is 7.3 x 1034. Is the forward or reverse reaction favored? Justify your answer.

b. At 25?C, the concentrations for this reaction were [N2O] = 0.55 M, [N2] = 0.12 M, and [O2] = 0.89 M. Is this reaction at equilibrium? If no, which direction will the reaction need to progress to reach equilibrium?

Explanation / Answer

at 25 C the given Kc >1 and is highly positive so the forward reaction is highly favourable. b> at this conc the calculated K = 0.0423 this is far less than the Kc value .hence the system is not in equilibrium to reach the eq this reaction shud go in fwd reaction

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