chlorine in a basic hydroxide solution produces chlorate and chloride ions. Writ

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2NaOH(aq) + Cl2(g) --> NaOCl(aq) + NaCl(aq) + H2O(l) ...keep in mind that the actual reaction is between OH- and chlorine gas. The sodium ion is a spectator ion. 2OH- + Cl2 --> Cl- + OCl- + H2O It involves the disproportionation of chlorine to form chlorine with two different oxidation numbers, -1 in Cl- and +1 in OCl-. here initially Cl2 molecule has 0 oxidation state, it changes in to -1 and +1 oxidation states. one element undergoes both oxidation and reduction known as disproportion reaction

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