What is the hybridization at each carbon atom in the molecule? Write hybridizati

Question

What is the hybridization at each carbon atom in the molecule? Write hybridizations starting on the left in molecule. http://session.masteringchemistry.com/render?expr=rraycolsep=0pt+egin{array}{ccccccccccccc}{ m+H}&&{ m+H}&&{ m+H}&&&&&&{ m+H}&&\{ m+|}&&{ m+|}&&{ m+|}&&&&&&{ m+|}&&\{ m+C}&{ m+=}&{ m+C}&{ m+-}&{ m+C}&{ m+-}&{ m+C}&{equiv}&{ m+C}&{ m+-}&{ m+C}&{ m+-}&{ m+H}\{ m+|}&&&&{ m+|}&&&&&&{ m+|}&&\{ m+H}&&&&{ m+H}&&&&&&{ m+H}&&end{array}

Explanation / Answer

The rule for hybridization: All sigma bonds (single bonds and only one bond in double or triple bonds) and lone pairs (nonbonding pairs) are found in hybrid orbitals. Since it is impossible to draw a structural formula in the answer part, it will be difficult to explain, but I'll try. Ethyl acetate: CH3 -- C = O .............................. I .............................. O -- CH2 --CH3 I think you understand the structure. First C atom has 4 single (sigma) bonds. therefore its type of hybridization is sp3 (1 s and 3 p = 4) Second C atom has 2 single(sigma) and 1 double bond (one of them is sigma , the other is pi bond). Total sigma bonds : 3. Since only sigma bonds are hybridized, its type of hybridization is sp2 (1 s and 2 p = 4) Third C atom has 4 single (sigma) bonds. (one with oxygen, one with 4th C atom and 2 with H atoms). Total sigma bonds: 4 and therefore the type of hybridization is sp3. Finaly the fourth C atom is like the first one and the type of the hybridization is sp3.

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