Solid potassium ,K , can be reacted with molecular oxygen , O2 to form K2O. If 4

Question

Solid potassium ,K , can be reacted with molecular oxygen , O2 to form K2O. If 4.3 g of potassium are reacted with 2 dm^3 of pure O2 at 20 degree celsius and 101.325 kPa what will be the mass and/or volumes of all substances present after the reaction is complete? Include the balanced reaction

Explanation / Answer

2 K + 0.5 O2 -> K2O 4.3 gm K = 4.3 /39 =0.11026 oxygen n = PV/RT , P = 101.325 KPa = 1 atm , V = 2 dm^3 = 2 liters n = 1x2/(0.0821 x 293) = 0.08314 0.11026 moles K reacts with (0.11026/4) O2 to give (0.11026/2) moles K2O O2 left 0.08314 - 0.027565 = 0.055 moles = 0.055 x32 = 1.76 gms O2 K2O produced = 94 x 0.055 = 5.18 gms will be present K will be absent

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