An individual has the genotype Ab/aB. Gene loci (A) and (B) are 15 cM apart. Ind
ID: 61577 • Letter: A
Question
An individual has the genotype Ab/aB. Gene loci (A) and (B) are 15 cM apart. Indicate all the possible gametes this individual can produce, and the proportions of expected progeny genotypes if a testcross is performed on this individual. An individual has the genotype Ab/aB. Gene loci (A) and (B) are 15 cM apart. Indicate all the possible gametes this individual can produce, and the proportions of expected progeny genotypes if a testcross is performed on this individual. An individual has the genotype Ab/aB. Gene loci (A) and (B) are 15 cM apart. Indicate all the possible gametes this individual can produce, and the proportions of expected progeny genotypes if a testcross is performed on this individual.Explanation / Answer
The gametes produced by an individual has the genotype Ab/aB are AB, aB, Ab, ab. Of these, AB, ab are recombinant and Ab, aB are parental. Given that the gene loci (A) and (B) are 15 cM apart. So, in the resulting gametes 15% of gametes are recombinant and remaining 85% will be similar to parental.
Thus, the percent gametes produced are, AB (7.5%), aB (42.5%), Ab (42.5%), ab (7.5%).
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