Why does the addition of 2 molar equivalents of HX to an alkyne yield the gemina

Question

Why does the addition of 2 molar equivalents of HX to an alkyne yield the geminal-dihalide Markovnikov product? Choose the best overall answer. Select one: After the first halogen has been added, the remaining alkene attacks and picks up a proton. At this stage, it is preferred to put the positive charge on the atom currently attached to a halogen because the halogen is electronegative. Through induction, the halogen will be able to pull electron density onto itself, thus stabilizing the adjacent and newly formed positive charge. The initial attack by the nucleophilic pi bonds is better able to receive the electrophilic proton on the side of the double bond that is not currently attached to a halogen. The carbocation formed after the 2nd addition of H+ is resonance stabilize by the lone pair of the halogen "pushing onto" the carbocation. all of the above A and B only B and C only None of the above

Explanation / Answer

e. a and b only

Related Questions

Navigate

• Browse (All)
• Browse W
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.