Zinc citrate (Zn_3(C_6H_5O_7)_2) is an ingredient in toothpaste. It is synthesiz

Question

Zinc citrate (Zn_3(C_6H_5O_7)_2) is an ingredient in toothpaste. It is synthesized by the reaction of zinc carbonate with citric acid. 3ZnCO_3(s) + 2C_6H_8O_7(aq) ---> Zn_3(C_6H_8O_7)_2(aq) + 3H_2O(l) + 3CO_2(g). If there are 5.1 mol of ZnCO_3 and 2.05 mol of C_6H_8O_7, how much Zn_3(C_6H_5O_7)_2 would be produced? Answer in units of mol.

Explanation / Answer

3ZnCO_3(s) + 2C_6H_8O_7(aq) ---> Zn_3(C_6H_8O_7)_2(aq) + 3H_2O(l) + 3CO_2(g). 3 moles of ZnCO3 reacts with 2 moles of C6H8O7 so 2.05 moles of C6H8O7 will react with 3/2 x 2.05 = 3.075 moles of ZnCO3 So ZnCO3 is in excess and C6H8O7 is Limiting reagent Moles of Zn3(C6H8O7)2 = 1/2 x 2.05 = 1.025 moles

Related Questions

Navigate

• Browse (All)
• Browse Z
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.