Given the accompanying table of mass percent and freezing temperature versus den

Question

Given the accompanying table of mass percent and freezing temperature versus density from the "Handbook of Chemistry and Physics," determine the mass percent of radiator liquid. %A(first column) is % by mass; D420 (second column) is density and the degreeree C is the difference in the freezing point between the mixture and the freezing point of water. (This is subtracted from 0 degreeree C) What is the mass percent of the antifreeze mixture? What is the freezing point of the mixture? Mass percent Freezing Point

Explanation / Answer

mass per = g of ethylene glycol / mass of solution -7.75 = -1.85 * (moles of Eg) Mass per = [ (moles of Eg) * (g/m of Eg) ] / [ (moles of Eg) * (g/m of Eg) +( mass of 1L of water) ]

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