Under the appropriate conditions, you can combine acetic acid and methanol to fo

Question

Under the appropriate conditions, you can combine acetic acid and methanol to form methyl acetate and water (see balanced equation below). You attempt this experiment in using 90.0 grams of acetic acid and 64.0 grams of methanol. You obtain an actual yield of 52.2 grams of methyl acetate. What is your percent yield? Report your answer to the nearest tenth of a percent, or one decimal place (e.g. XX.X%).

Explanation / Answer

CH3COOH + CH3OH -----> C3H6O2 + H2O moles of reactants- HOAc: 90.0 g/ 60.05 g/mole acetic acid= 1.5 moles acetic acid CH3OH: 64.0 g/ 32.04 g/mole methanol= 2.0 moles methanol acetic acid is limiting reactant 1.5 moles HOAc x 74 g/mole methyl acetate= 111 g theo. amt. of ester % yield= act/theo. x 100 % yield= 52.2 g/ 111 g x 100= 47.0 %

Related Questions

Navigate

• Browse (All)
• Browse U
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.