2I- (aq) + S2O82- (aq) ? I2 (aq) + 2SO42- (aq) The following rate data was colle

Question

2I- (aq) + S2O82- (aq) ? I2 (aq) + 2SO42- (aq) The following rate data was collected by measuring the time required for the appearance of the blue color due to the iodine-starch complex. Trial [I-] [S2O82-] Reaction Time 1 0.040 M 0.040 M 270sec 2 0.080 M 0.040 M 138 sec 3 0.040 M 0.080 M 142 sec 1. In each trial, the blue color appeared after 0.0020 M iodine (I2) had been produced. Calculate the reaction rate for each trial by dividing the concentration of iodine formed by the reaction time. 2. Compare trials 1 and 2 to determine the order of reaction with respect to iodide ions. How did the concentration of iodide ions change in these two trials, and how did the rate change accord

Explanation / Answer

Trial 1 0.0020M / 270sec = 0.0000074 moles/(L sec) Trial 2 0.0020M / 138sec = 0.000014 moles/(L sec) Trial 3 0.0020M / 142sec = 0.000014 moles/(L sec) You are correct, you want 1 and 3 because all other concentrations must be held constant, except for the one you are looking at.

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