Hydrogen iodide, HI, decomposes at moderate temperatures according to the equati

Question

Hydrogen iodide, HI, decomposes at moderate temperatures according to the equation shown below. The amount of I2 in the reaction mixture can be determined from the intensity of the violet color of I2; the more intense the color, the more I2 in the reaction vessel. When 4.00 mol of HI was placed in a 5.00 L vessel at 458 oC, the equilibrium mixture was found to contain 0.442 mol of I2. What is the value of Kc for the decomposition of HI at this temperature? 2HI(g) <--- H2(g) + I2(g) --->

Explanation / Answer

2HI--- > H2 + I2 initial 4 0 0 final 3.116 0.442 0.442 so Kc=[H2][I2]/[HI]^2 =0.442*0.442/3.116*3.116 =2.01*10^-2

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