Find the concentration of CrO42 Solution a) BaCrO4 --> Ba2+ + CrO42-. The expres

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a) BaCrO4 --> Ba2+ + CrO42-. The expression for Ksp is [Ba2+][CrO42-], and since we have 1.08 x 10^-5 M BaCrO4, each of those concentrations is 1.08 x 10^-5. Hence Ksp is (1.08 x 10^-5)^2 = 1.17 x 10^-10 b) Same procedure, except Ag2SO3 --> 2Ag+ + SO3(2-), so the Ksp expression is [Ag+]^2[SO3(2-)]. c) Same procedure, except Pd(SCN)2 --> Pd(2+) + 2SCN-. You should be able to follow the procedure by now to guess what the Ksp expression is and what numbers to put in to compute its value.

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