Acetaldehyde decomposes to methane and carbon monoxide as follows...CH3CHO (g)--

Question

Acetaldehyde decomposes to methane and carbon monoxide as follows...CH3CHO (g)------>CH4 (g) + CO (g) at 527 degrees Celsius. Its rate law expression is Rate = k[CH3CHO]^2, the specific rate constant at 527 degrees celsius is k = 2.0 x 10^-2 M^-1 hr^-1. WHAT IS THE ORDER WITH RESPECT TO ACETALDEHYDE. WHAT IS THE HALF-LIFE IF 0.10 MOLE OF CH3CHO IS INJECTED INTO AN EMPTY 1.0 L VESSEL AT 527 DEGREES CELSIUS SHOW ALL WORK. HOW MANY MOLES OF CH3CHO REMAIN AFTER 200 HOURS SHOW ALL WORK. WHAT PERCENT OF CH3CHO REMAINS AFTER 200 HOURS SHOW ALL WORK.

Explanation / Answer

a) second, b) t1/2 = 500 hrs, c) 0.071 mol, d) 71%, e) t1/2 = 5000 hrs, f) 0.096 mol, g) 96% plsz rate me 1st

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.