In chickens, having feathers on legs is dominant to having featherless legs. In

Question

In chickens, having feathers on legs is dominant to having featherless legs. In a population of 200 chickens, 128 have featherless legs. How many chickens are heterozygous for the “feathered leg” allele? Assume the population is in Hardy-Weinberg equilibrium.

In chickens, having feathers on legs is dominant to having featherless legs. In a population of 200 chickens, 128 have featherless legs. How many chickens are heterozygous for the “feathered leg” allele? Assume the population is in Hardy-Weinberg equilibrium.

Explanation / Answer

Hardy-Weinberg law states p+q= 1

Featherless legs (recessive)= 128 out of 200, so the percentage is 64 or frequency is 0.64, so 0.8 is p

p+q=1

p+0.8= 1

p= 0.2

p2+2pq+q2

2pq represents the hereozygotes

2 x 0.8 x 0.2= 0.32 or 32%

32% of 200 is 64

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