Three solutions are mixed together to form a single solution. One contains 0.2 m

Question

Three solutions are mixed together to form a single solution. One contains 0.2 mol Pb(CH3COO)2 , the second contains 0.1 mol NA2S, and the third contains 0.1 mol CaCl2 . A) Write the net ionic equations for the precipitation reaction or reactions that occur. Express your answer as a balanced net ionic equation. Identify all of the phases in your answer.If there is more than one answer, separate them by a comma. B)What are the spectator ions in the solution? Express your answer as an ion. If there is more than one answer, separate them by a comma. Thanks!

Explanation / Answer

molecular equation should start with 2Pb(C2H3O2)2 + Na2S + CaCl2 (notice the 2 Pb(C2H3O2)2, due to the molar ration of 2:1:1), but the only way I can get it to balance is Pb(C2H3O2)2 + Na2S + CaCl2 --> Ca(C2H3O2)2 + PbS + 2NaCl Then the Ionic Equation Pb + 2C2H3O2 + 2Na + S + Ca + 2Cl --> Ca + 2C2H3O2 + PbS + 2Na + 2Cl The Net Ionic Equation Pb + S --> PbS Both Lead Sulphide and Lead Chloride are insoluble. Pb++ + S - - ------> PbS? and Pb++ + 2Cl - ------> PbCl2 ? Specatator ions are Acetate, Sodium, and Calcium

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