Sodium phosphate is added to a solution that contains 0.0031 M aluminum nitrate

Question

Sodium phosphate is added to a solution that contains 0.0031 M aluminum nitrate and 0.020 M calcium chloride. The concentration of the first ion to precipitate (either Al3+or Ca2+) decreases as its precipitate forms. What is the concentration of this ion when the second ion begins to precipitate?

Sodium phosphate is added to a solution that contains 0.0031 M aluminum nitrate and 0.020 M calcium chloride. The concentration of the first ion to precipitate (either Al3+or Ca2+) decreases as its precipitate forms. What is the concentration of this ion when the second ion begins to precipitate?

Explanation / Answer

These are the reactions: 2Na3PO4 + 3CaCl2 ? 6NaCl + Ca3(PO4)2? Na3PO4 + Al(NO3)3= AlPO4? + 3 NaNO3 as we know.. Calcium is more reactive than Aluminum So it will react first and form precipitate The answer is ...Aluminum will not form precipitate until all Calcium have reacted because as long as Calcium is present .. it has the upper hand so The answer is ... the concentration of Ca2+ will be zero when Al3+ starts to precipitate.

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