Aluminum reacts with chlorine gas to form aluminum chloride via the following re

Question

Aluminum reacts with chlorine gas to form aluminum chloride via the following reaction: 2Al(s) + 3Cl2(g) -----> 2AlCl3(s) You are given 20.0 g of aluminum and 25.0 g of chlorine gas 1. If you had excess chlorine, how many moles of aluminum chloride could be produced from 20.0g of aluminum? Express your answer to three sig figs and include the appropriate units. 2. If you had excess aluminum, how many moles of aluminum chloride could be produced from 25.0 of chlorine gas, ? Express your answer to three significant figures and include the appropriate units.

Explanation / Answer

1.

2Al + 3Cl2 ....> 2AlCl3

no. of moles = given mass/molar mass

20.0/26.98

=0.741 mol

2.

(25/70.9)/3 X 2

=0.235 mol

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