Hello, The answer to this problem is 0.01g. I have tried this problem multiple t
ID: 6274 • Letter: H
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Hello, The answer to this problem is 0.01g. I have tried this problem multiple times and I can't get that answer. Please help me find my mistake by showing all your work. Thank you very much! As the lab instructor for cell biology, you need to make a solution of DCMU, an inhibitor of photosynthetic electron transport. you want a final concentration of 2 x 10-5 M in a final volume of 1.25 mls, and this needs to be achieved using a 10 µl shot from the pipet. how much DCMU should weigh out to dissolve in 10mls of alcohol? the MW of DCMU is 400 g/mol? Hello, The answer to this problem is 0.01g. I have tried this problem multiple times and I can't get that answer. Please help me find my mistake by showing all your work. Thank you very much! As the lab instructor for cell biology, you need to make a solution of DCMU, an inhibitor of photosynthetic electron transport. you want a final concentration of 2 x 10-5 M in a final volume of 1.25 mls, and this needs to be achieved using a 10 µl shot from the pipet. how much DCMU should weigh out to dissolve in 10mls of alcohol? the MW of DCMU is 400 g/mol?Explanation / Answer
by the dilution equation M1V1=M2V2 M= moles of substance per Liters of Volume= mols/L M2=2.5x 10^-5 mols/L V2= 1.25mL (converted to liters at 1000mL=1L)= .00125L V1=10uL (converted to liters at 1000000uL=1L)= .000010L now plugging it in and rearranging M1 = (.00125L * 2.5 x 10^-5M)/ (,000010L)= .003125M So your target molarity for the 10uL shot is M1 (which is moles DCMU disolved in 10 uL alcohol) M=mols/L so rewrite M1 to figure out how many moles you need in that 10uL shot M1= .003125 mols/L * .000010L = .000000031 or 3.1x10^-8 moles needed and we know how many grams make up a mole from the MW= 400g/mol 3.1x10^-8 moles * (400g/1mol) = .000125 or 1.25x10^-5 grams DCMU moles cancel leaving you an answer in grams!
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