Copper forms two different cations, cuprous (Cu+) and cupric (Cu2+). When solid
ID: 627742 • Letter: C
Question
Copper forms two different cations, cuprous (Cu+) and cupric (Cu2+). When solid copper reacts with silver nitrate solution, two reactions are possible, as shown in equations a and b. a) Molecular Equation: Cu(s) + AgNO3(aq) ? CuNO3(aq) + Ag(s) Net Ionic Equation: Cu(s) + Ag+(aq) ? Cu+(aq) + Ag(s) b) Molecular Equation: Cu(s) + 2AgNO3(aq) ? Cu(NO3)2(aq) + 2Ag(s) Net Ionic Equation: Cu(s) + 2Ag+(aq) ? Cu2+(aq) + 2Ag(s) 1. What mass of metallic silver can form from 1.347 g of copper metal according to Equation a? 2. What mass of metallic silver can form from 1.347 g of copper metal according to Equation b? 3. A student reacts 1.347 g of copper with a solution containing excess silver nitrate and recovers 2.248 g of silver metal. Which reaction, a) or b), most likely occurred in the experiment? Explain your answer completely.Explanation / Answer
we know that molar mass of silver (Ag)=108g molar mass of copper (Cu)=63.5g a) considering the reaction a has taken place Cu(s) + AgNO3(aq) ? CuNO3(aq) + Ag(s) we can seen that 1 mole of silver Ag(s) is precipitated by 1 mole of Cu(s) Cu(s) + Ag+(aq) ? Cu+(aq) + Ag(s) hence, the amount of silver (Ag) precipitated from 1.347g of copper (Cu) is (1.347/63.5)*108=2.290g. b) considering the reaction b has taken place Cu(s) + 2AgNO3(aq) ? Cu(NO3)2(aq) + 2Ag(s) we can seen that 2 moles of silver Ag(s) is precipitated by 1 mole of Cu(s) Cu(s) + 2Ag+(aq) ? Cu2+(aq) + 2Ag(s) hence,the amount of silver (Ag) precipitated from 1.347g of copper (Cu) is (1.347/63.5*2)*108=1.145g c)The amount of silver (Ag) obtained by reacting 1.347g of copper (Cu) is 2.248g,which nearly equals to that of silver formed in reaction a. x(2.29)+(1-x)1.145=2.248 which implies x=0.9633. hence,the amount of silver formed by reaction a is =96.33% the amount of silver formed by reaction b is=3.66% therefore,most of the silver is formed following reaction a
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