At 25 Solution similar solutions helpful to you the reaction 2 N2O + 3 O2 -->2 N

Question

Explanation / Answer

similar solutions helpful to you the reaction 2 N2O + 3 O2 -->2 N2O4 Kc = [N2O4]^2 / [N2O]^3 [O2]^3 can be found from: (A) N2 + 1/2 O2 --> N2O (B) N2O4 --> 2NO2 (C) 1/2 N2 + O2 --> NO2 by combining.... the reverse of 2 equation (A)'s in order to get 2 N2O 's as reactants the reverse of 2 equation (B) 's in order to get 2 N2O4 's as products & 4 equation (C) 's in order to cancel out the 2 N2 's from 2(A)'s , & the 4 NO2 's from 2(B)'s reverse of 2 (A): 2 N2O --> 2 N2 + 1 O2 reverse of 2 (B): 4 NO2 --> 2 N2O4 & 4 times (C) : 2 N2 + 4 O2 --> 4 NO2 note that 4 NO2 --> cancels --> 4 NO2 2 N2 --> cancels --> 2 N2 4 O2 --> cancels --> 1 O2 leaving 3 O2 's as reactants giving you what you wanted: 2 N2O + 3 O2 -->2 N2O4 so if the reverse of 2 (A)'s & reverse of 2 (B)'s & 4 (C)'s gives you what you want, then K = (Kc)^4 / (Ka)^2 (Kb)^2 K = (4.1 x 10E-9.)^4 / (2.7 x 10E-18)^2 (4.6 x 10E-3)^2 K = (2.826 e-34) / (7.29 e-36) (2.116 e-5) K = (2.826 e-34) / (71.543 e-40) K = 1.832 e6 your answer rounded to 2 sig figs is Kc = 1.8 e+6

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.