H2 g + I2 g 2HI g: The value of Kp fo the reaction is 61 at 770C. What is the eq
ID: 630915 • Letter: H
Question
H2 g + I2 g 2HI g: The value of Kp fo the reaction is 61 at 770C. What is the equilibrium partial pressure of HI in a sealed reaction vessel at 770C if the initial partial pressures of H2 and I2 are both .120atm and initially there is no HI present? Please show the work. I need to figure out what I am doing wrong! My ICE table is as follows: I: PH2 = 0.120 PI2=0.120 P(HI)^2=0 C: -x -x 2x E: (.120-x) (.120-x) 2x After the quadratic equation, I end up with 2 negative #'s. I know I am doing something wrong because partial pressure cannot be negative.Explanation / Answer
......H2....+....I2.......<=>....2 HI
I....0.120......0.120...........0
C.....-a............-a...........+2a
E...0.120-a..0.120-a......2a
Kp = P(HI)^2/P(H2)P(I2)
= (2a)^2/(0.120 - a)^2 = 61
2a/(0.120 - a) = 61^(1/2) = 7.810
9.810a = 0.9372
a = 0.09554
P(HI) = 2a = 0.191 atm
(Note that there is no need to solve any quadratic equation. Please rate the answer. Thanks.)
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