plusminus Nuclear Binding Energy per Nucleon Nuclear binding energy, Delta E, is

Question

plusminus Nuclear Binding Energy per Nucleon Nuclear binding energy, Delta E, is the energy required to break a nucleus into its component nucleons (protons and neutrons). It can also be defined as the energy released when a nucleus forms from its component nucleons. Using Einstein's equation one can calculate nuclear binding energy in joules: Delta E = (Delta m)c2 where Delta m is the mass defect in kilograms and c is the speed of light in meters per second. The mass defect is the difference in mass between the nucleus and its components. The stability of different nuclei can be compared by using the average nuclear binding energy per nucleon, which can be obtained by dividing the nuclear binding energy by the mass number. The atomic mass of 55/25Mn is 54.938 amu. The speed of light is c = 3.00 times 108 m/s. The mass of a proton is 1.0073 amu. The mass of a neutron is 1.0087 amu. The mass of an electron is 5.4858 times 10-4 amu. 1 kg = 6.022 times 1026 amu. 1 J = 1 kg middot m2/s2. 1 MeV = 1.602 times 10-13 J. Calculate the nuclear binding energy of 55/25Mn in joules. Express your answer numerically in joules. plusminus Nuclear Decay Calculations Radioactive decay is characterized by the equation where N0 is the initial amount, N is the amount Phosphorus-32 decays by beta emission to form sulfur-32. How many half-lives have passed in the reaction shown here? (Figure 1) Express your answer as an integer. The half-life of phosphorus-32 is 14.26 days. Calculate its decay constant. Express the decay constant numerically in inverse days. If you accidentally spill phosphorus-32 onto your shoe, how long would it take before 99.9% of the radioactive material has decayed so that you can safely wear the shoes again? Express your answer as an integer.

Explanation / Answer

for Question 2) 3 half lives have passed

for question 3) 142.55 days (taken phosphorus-32 half life = 14.3 days)

for question 1) Total mass of nucleons = 30.261+25.1825
Total mass of nucleons = 55.4435 amu

55.4435-54.938=0.5055 amu

E=?mc^2
E=(8.3942x10^-28)(3x10^8)^2
E=7.55x10^-11 J

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