Question 4 1 pts In an existing process, 180 kgmol/h of C,H, (P) is mixed with 4

Question

Question 4 1 pts In an existing process, 180 kgmol/h of C,H, (P) is mixed with 420 kgmol/h of a mixture containing 50% CO (C) and 50% H2 (H) and with a recycle stream containing propylene and then fed to a reactor, 30% of the propylene fed to the reactor is consumed. The reactor effluent is sent to a separator. The desired product butanal (B) is removed in one stream, unreacted CO and H, are removed in a second stream, and unreacted P is recovered and recycled. 5 er Reactor Separator - -K, H P, c, C, H 2 7 What is the mol% butanol in the reactor effluent (stream 4)? Round to the nearest 0.1%

Explanation / Answer

1-

Balance H around mixer

H2 = H3

Balance H around reactor

H3 = H(cons) + H4

H4 = H3 - H(cons)

H4 = H2 - H(cons)

H4 = 420*0.5 - 180 = 30 kmol

Balance P around reactor

30% P consumed means 70% P unreacted

P4 = 0.7*P3

Balance C around mixer

C2 = C3

Balance C around reactor

C3 = C(cons) + C4

C4 = C3 - C(cons)

= 420*0.5 - 180 = 30 kmol

P1 = P(cons)

P3 = 180 kmol

P4 = 180*0.70 = 126 kmol

P4 = P5 = 126 kmol

B4 = B(gen) = 180*0.3 = 54 kmol = P(cons)......... Eq1

B4 = B7 = 54 kmol...... Eq2

P1 + P5 = P3

P1 = 180 - 126 = 54 kmol........ Eq3

From eq3 and eq1

P1 = P(cons)

Total kmol of stream 4

= P4 + C4 + H4 + B4 = 126 + 30 + 30 + 54 = 240 kmol

Mol% butanal = B4/stream 4

= 54*100/240

= 22.5 %

Related Questions

Navigate

• Browse (All)
• Browse Q
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.