Objective Knowledge Check Question 9 enala Acetic acid and ethanol react to form
ID: 635389 • Letter: O
Question
Objective Knowledge Check Question 9 enala Acetic acid and ethanol react to form ethyl acetate and water, like this: HCH, CO (aa)CH,OH(x) C2H,CO CH (ag)+H20(0) Imagine 173. mmol of C2H,CO2CH, are removed from a flask containing a mixture of HCH, Co2, C,H,OH, C,H,CO,CH, and H,0 at equnibrium, and then answer the following questions. e Zero. wndtion before ary teo.Greater but O Greater than zero, but less than the rate of the forward reation. reaction before any C2HCO20% the flask Greater than zero, and equal to the rate of the forward reaction. O Greater than zero, and greater than the rate of the ferward reaction O Zero. o Greater than zero, but less than the rate of the forward reaction. reaction just after the CaHsCO2CH2 has been removed from the flask? Greater than zero, and equal to the rate of the forward reaction. ) Greater than zero, and greater than the rate of the forward reaction @) Zero. What is the rate of the reverseGreater than zero, but less than the rate of the forward reaction. reaction when the systern has again reached equilibrium? O Greater than zero, and equal to the rate of the forward reaction. D Greater than zero, and greater than the rate of the forward reaction. None. How much less C2Hs00-CHs is inSome. but less than 173. mmol. the flask when the system has sasin nschnd.nsilibium I Don't KnowExplanation / Answer
At equilibrium conditions
Rate of forward reaction = Rate of reverse reaction
The final mixture is in equilibrium
From the Le Chatelier's principle if moles of product has been removed from the mixture, the reaction proceeds in the forward reaction and achieve the new equillibrium.
Part a
Before removal
The system at equilibrium
Rate of forward reaction = Rate of reverse reaction
Rate of reverse reaction greater than 0 and equal to the Rate of forward reaction.
Part b
After removal
The reaction proceeds in forward direction.
Rate of reverse reaction greater than 0 and less than Rate of forward reaction
Part c
At new equillibrium
Rate of reverse reaction greater than 0 and equal to the Rate of forward reaction.
Part d
At new equillibrium
Since moles of C2H5CO2CH3 removed then at the new equillibrium moles of C2H5CO2CH3 will be less than before.
Some, but less than 173 mmol
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