In a galvanic cell, one half-cell consists of a tin strip dipped into a 1.00 M s

Question

In a galvanic cell, one half-cell consists of a tin strip dipped into a 1.00 M solution of Sn(NO3)h. In the second half-cell, solid rhodium is in contact with a 1.00 M solution of Rh(NO3)3. Rh is observed to plate out as the galvanic cell operates, and the initial cell voltage is measured to be 0.898 V at 25°C. (a) Write balanced equations for the half-reactions at the anode and the cathode. Show electrons as e. Use the smallest integer coefficients possible and the pull-down boxes to indicate states. If a box is not needed, leave it blank Half-reaction at anode (do not multiply by factor): Half-reaction at cathode (do not multiply by factor): (b) Calculate the standard reduction potential of a Rh3tRh half-cell. The standard reduction potential of the Sn2+ Sn electrode is-0.140 y

Explanation / Answer

Half reaction at anode

Sn(s) ----------------> Sn^2+ (aq) + 2e^-                  

Half reaction at cathode

Rh^3+ (aq) + 3e^- ------------------> Rh(s)

3Sn(s) ----------------> 3Sn^2+ (aq) + 6e^-                  E0   = 0.14v

2Rh^3+ (aq) + 6e^- ------------------> 2Rh(s)               E0   = x

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3Sn(s) + 2Rh^3+ (aq) ----------> 3Sn^2+ (aq) + 2Rh(s)     Ecell   = 0.14+x

Ecell   = 0.14+x

0.898   = 0.14+x

x   = 0.758v

The standard reduction potential of Rh^3+/Rh is 0.758v >>>>answer

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