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Question

ilrn/takeAssi ignment/takeCovalentActivity.do?locator-assignment-take&takeAssignmentSessi; Use the References to access impertant values if needed for this Zine metal reacts with excess hydrochloric acid to produce hydrogen gas according to the following equation: Zn(s)+ 2HCIKag) ZnCl(a) H) The product gas, H2, is collected over water at a temperature of 20 "C and a pressure of 748 mm Hg. If the wet H2 gas formed occupies a volume of S.11 L, the sumber of grams of Hy formed is The vapor pressure of water is 17.5 mm Hg at 20'C. Submit Answer Rety Entire Group 9 more group attempts remaining

Explanation / Answer

Given:

P = 748 mmHg - 17.5 mmHg

= 730.5 mm Hg

= (730.5/760) atm

= 0.9612 atm

V = 8.11 L

T = 20.0 oC

= (20.0+273) K

= 293 K

find number of moles using:

P * V = n*R*T

0.9612 atm * 8.11 L = n * 0.08206 atm.L/mol.K * 293 K

n = 0.3242 mol

Molar mass of H2 = 2.016 g/mol

use:

mass of H2,

m = number of mol * molar mass

= 0.3242 mol * 2.016 g/mol

= 0.6536 g

Answer: 0.654 g

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