please answer both questions Pre-Lab Assignment 5 (detach and submit to your TA

Question

please answer both questions

Pre-Lab Assignment 5 (detach and submit to your TA at the beginning of your lab session) TA Name Date: The following reactions of three metals X, Y and Z are observed to proceed in the forward direction X (s) + Z2+ (aq)-X2+ (aq) + Z (s) Z (s) + Y2 (aq) Z2 (aq)+ (s) 1. If a piece of metal Y was placed in a solution of X? (aq), would a reaction occur, and if so what woulb be? Briefly explain the reasoning for your answer A piece of metal Z placed in a solution of 1M HCI dissolves and releases hydrogen gas. Will the melal X also dissolve in this HCI solution? Why? 2. 60

Explanation / Answer

1) X(s) + Z2+(aq) - - - - - - > X2+(aq) + Zn(s)

Z(s) + Y2+(aq) - - - - - - > Z2+ (aq) + Y(s)

i) No, reaction will not occur

ii) reason

From the above two reaction, it is known that standard reduction potential order is Y2+/Y > Z2+/Zn > X2+/X i.e Y is more likely to be in reduced state than both X and Z and Z is more likely to be in reduced state than X. So, if piece of metal Y is placed in X2+ solution, no reaction will occure because reduction potential of Y2+ to Y is higher than the reduction potential of X2+ to X.

We can compare X,Z, and Y with Zn, Pb and Cu

Zn2+ to Zn reduction potential = - 0.763V

Pb2+ to Pb reduction potential = - 0.126V

Cu2+ to Cu reduction potential = +0.337V

2)

i) Yes, X also dissolve in the given HCl solution

ii) In general, lower the reduction potential of an element higher will be it's raactivity.As we discuss above, X lower in reduction potential than Z, so, if Z is replaced H2 from HCl, then X should replace H2 from HCl.

  

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