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cca.desire2learn.com | CHE1124NO Gen College Cherm II/Lab: SCI (Tiff.. ent Grades Attendance Dropbox Discussions AssessmentsClasslist Communication tration prelab ggg | A Reso Time Left:0:37:40 Sadiya Said: Attempt 1 Save Question 2 (4 points) when a certain mass of the solid acid potassium hydrogen phthalate, KHP was dissolved in water, 25.0 ml of 0.100 M sodium hydroxide were needed to get the to the equivalence point. How many grams of KHP were used? The molar mass of KHP is 204.2 g/mol A) 0.5105 g B).511 g D) 5.11 g se.. Save MacBook Air

Explanation / Answer

Moles of NaOH required for equivalent point( ie neutralization )=(0.1 moles per litre) * (0.025 Litre)=0.0025 moles

Same number of moles of KHP were present in the solution before neutralization.

So the gram of KHP used = moles* molecular wt= 0.0025*204.2=0.5105 gm

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