C programming: Assign to maxSum the max of (numA, numB) PLUS the max of (numY, n

Question

C programming:

Assign to maxSum the max of (numA, numB) PLUS the max of (numY, numZ). Use just one statement. Hint: Call FindMax() twice in an expression.

#include <stdio.h>

double FindMax(double num1, double num2) {

double maxVal = 0.0;

// Note: if-else statements need not be understood to complete this activity

if (num1 > num2) { // if num1 is greater than num2,

maxVal = num1; // then num1 is the maxVal.

}

else { // Otherwise,

maxVal = num2; // num2 is the maxVal.

}

return maxVal;

}

int main(void) {

double numA = 5.0;

double numB = 10.0;

double numY = 3.0;

double numZ = 7.0;

double maxSum = 0.0;

/* Your solution goes here */

printf("maxSum is: %.2f ", maxSum);

return 0;

}

Explanation / Answer

#include <stdio.h>

double FindMax(double num1, double num2) {

double maxVal = 0.0;

// Note: if-else statements need not be understood to complete this activity

if (num1 > num2) { // if num1 is greater than num2,
maxVal = num1; // then num1 is the maxVal.
}
else { // Otherwise,
maxVal = num2; // num2 is the maxVal.
}
return maxVal;
}

int main(void) {

double numA = 5.0;

double numB = 10.0;

double numY = 3.0;

double numZ = 7.0;

double maxSum = 0.0;
  
maxSum= FindMax(numA,numB)+ FindMax(numY,numZ);

printf("maxSum is: %.2f ", maxSum);

return 0;

}

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