EASY PHP SCRIPT PROBLEM! Would prefer you to take screen shot of code and upload

Question

EASY PHP SCRIPT PROBLEM!                                                                                                                                    

Would prefer you to take screen shot of code and upload the screenshot(s) as the answer.

Below is a PHP code example to follow when scripting the problem above:

$percentGrade = 0.0;
$letterGrade = "X";

printf(" Enter Percent Grade: ");
fscanf(STDIN, "%f", $percentGrade);

if( $percentGrade >= 90 )
{
$letterGrade = "A";
}
else
{
if( $percentGrade >= 80 )
{
   $letterGrade = "B";
}
else
{
   if( $percentGrade >= 70)
   {
  $letterGrade = "C";
   }
   else
   {
  if($percentGrade >= 60)
  {
    $letterGrade = "D";
  }
  else
  {
    $letterGrade = "F";
  }
   }
}
}
printf(" The letter grade is %s",$letterGrade);

fscanf(STDIN, "%s", $buster);
?>

Explanation / Answer

Algorithm:
Read loanAmount
Set deposit to zero
Set display_output to blank
If loanAmount >= 0 And loanAmount < 25000 Then
    deposit = loanAmount* 5%
    display_output = Currency format of deposit
Else
    If loanAmount >= 25000 And loanAmount <= 49999 Then
        deposit = 1250 + (loanAmount - 25000) * 10%
        display_output = Currency format of deposit
    Else
         If loanAmount >= 50000 And loanAmount <= 100000 Then
            deposit = 5000 + (loan_amount - 50000) * 25%
            display_output = Currency format of deposit
         Else
            display_output = "Error: Loan amount not within acceptable range "
------------------------------------------------------------------------------------------------

PHP Code:

<?php
$loanAmount;
$deposit=0;

printf(" Enter Loan amount: ");
fscanf(STDIN, "%f", $loanAmount);
if($loanAmount >= 0 && $loanAmount < 25000)
{
$deposit = $loanAmount* 0.05;
printf("The deposit is: $ %s", $deposit);
}
else
{
if($loanAmount >= 25000 && $loanAmount <= 49999)
{
$deposit = 1250 + ($loanAmount - 25000) * 0.1;
printf("The deposit is: $ %s", $deposit);
}
else
{
if($loanAmount >= 50000&& $loanAmount <= 100000)
{
$deposit = 5000 + ($loan_amount - 50000) * 0.25;
printf("The deposit is: $ %s", $deposit);

}
else
{
printf("Error: Loan amount not within acceptable range");
}
}
}

?>

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